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    x^2
    x^{\msquare}
    \frac{\msquare}{\msquare}
    \sqrt{\square}
    f(x)
    \infty
    \mathrm{or}
    \cup
    \le
    \ge
    (\square,\square)
    \mathrm{None}
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    x^2
    x^{\msquare}
    \frac{\msquare}{\msquare}
    \sqrt{\square}
    f(x)
    \infty
    \mathrm{or}
    \cup
    \le
    \ge
    (\square,\square)
    \mathrm{None}
    Skip Question Next
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      x^2 x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div x^{\circ} \pi
      \left(\square\right)^{'} \frac{d}{dx} \frac{\partial}{\partial x} \int \int_{\msquare}^{\msquare} \lim \sum \infty \theta (f\:\circ\:g) H_{2}O
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